2. Abstract
We weight the educts and products while we did the experiment, that we can see how the chemical equation is balanced.
3. Introduction
We mixed Na(2)CO(3) and HCl together. The reaction began and the product CO(2) came out as a gas. The residue was NaCl + H(2)O.
4. Procedure
We put Na(2)CO(3) on the one side of the glass and the HCl(aq) on the other side. Then we took the funnel and stuck it in a rubber and put both in the glass that no gas comes out. Then we took the cylinder and filled it up with water and put it upside down in a beaker full of water. There should be no gas…
